8[y+3]=3[2y+12]

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Solution for 8[y+3]=3[2y+12] equation:


Simplifying
8[y + 3] = 3[2y + 12]

Reorder the terms:
8[3 + y] = 3[2y + 12]
[3 * 8 + y * 8] = 3[2y + 12]
[24 + 8y] = 3[2y + 12]

Reorder the terms:
24 + 8y = 3[12 + 2y]
24 + 8y = [12 * 3 + 2y * 3]
24 + 8y = [36 + 6y]

Solving
24 + 8y = 36 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
24 + 8y + -6y = 36 + 6y + -6y

Combine like terms: 8y + -6y = 2y
24 + 2y = 36 + 6y + -6y

Combine like terms: 6y + -6y = 0
24 + 2y = 36 + 0
24 + 2y = 36

Add '-24' to each side of the equation.
24 + -24 + 2y = 36 + -24

Combine like terms: 24 + -24 = 0
0 + 2y = 36 + -24
2y = 36 + -24

Combine like terms: 36 + -24 = 12
2y = 12

Divide each side by '2'.
y = 6

Simplifying
y = 6

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